我是一个python入门的小白，做这个系列即是为了巩固pygame的相关知识，也是为了考验自己坚持做一件事。
另外如果以下内容有错误或不规范的请各位大佬积极指出，谢谢大家

获取键盘事件

在Pygame中，键盘事件主要包括KEYDOWN和KEYUP 两种类型。KEYDOWN 事件表示某个键被按下，而KEYUP 事件表示某个键被释放。 可以通过 pygame.event.get() 函数获取这些事件。

for event in pygame.event.get(): 
    if event.type  == pygame.KEYDOWN:
        # 键盘按下事件处理 
        pass 
    elif event.type  == pygame.KEYUP:
        # 键盘释放事件处理 
        pass 

在这里我给出一个按下键盘的案例 —— 移动正方形:

'''
用键盘移动正方形移动
'''
import pygame
import sys

#初始化pygame
from pygame.locals import*
pygame.init()

#创建游戏窗口
width =640
height = 480
screen = pygame.display.set_mode((width,height))

#给游戏窗口命名
pygame.display.set_caption("原来是稀琳")

#正方形变量
rect_x = width / 2
rect_y = height / 2
rect_width = 20
rect_height =20
rect_color = (0,225,0)
rect_size = 20
rect_speed = 20
rect_direction = 'RIGHT'

#控制帧率
game_clock = pygame.time.Clock()

runing = True
while runing:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            runing = False

        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_UP and event.key != 'DOWN':
                rect_direction = 'UP'
            elif event.key  == pygame.K_DOWN and rect_direction != 'UP': 
                rect_direction = 'DOWN' 
            elif event.key  == pygame.K_LEFT and rect_direction != 'RIGHT': 
                rect_direction = 'LEFT' 
            elif event.key  == pygame.K_RIGHT and rect_direction != 'LEFT': 
                rect_direction = 'RIGHT' 
    if rect_direction == 'UP':
        rect_y -= rect_speed
    elif rect_direction == 'DOWN':
        rect_y += rect_speed
    elif rect_direction == 'LEFT':
        rect_x -= rect_speed
    elif rect_direction == 'RIGHT':
        rect_x += rect_speed

    if rect_x < 0:
        rect_direction = 'RIGHT'
    elif rect_x > width:
        rect_direction = 'LEFT'
    elif rect_y < 0:
        rect_direction = 'DOWN'
    elif rect_y > height:
        rect_direction = 'UP'


    #更新画面
    screen.fill((0,0,0))

    #画出正方形
    pygame.draw.rect(screen,rect_color,(rect_x,rect_y,rect_width,rect_height),rect_size)

    # 更新显示 
    pygame.display.flip()  

    # 控制帧率 
    pygame.time.Clock().tick(10) 

    #刷新游戏窗口
    pygame.display.update()

#关闭游戏窗口
pygame.quit()
sys.exit()

接下来我会详细的讲解上述代码的意思:

1、画出正方形

2、定义正方形的速度和初始运动变量

rect_speed = 20
rect_direction = 'RIGHT'

3、键盘交互与一些基本运动逻辑

for event in pygame.event.get():
        if event.type == pygame.QUIT:
            runing = False

        elif event.type == pygame.KEYDOWN:
            '''为了让正方形在按键时合理运动'''
            if event.key == pygame.K_UP and event.key != 'DOWN':  # 向上运动时不能控制它向下运动
                rect_direction = 'UP'
            elif event.key  == pygame.K_DOWN and rect_direction != 'UP': 
                rect_direction = 'DOWN' 
            elif event.key  == pygame.K_LEFT and rect_direction != 'RIGHT': 
                rect_direction = 'LEFT' 
            elif event.key  == pygame.K_RIGHT and rect_direction != 'LEFT': 
                rect_direction = 'RIGHT' 
    ''' 键盘控制它持续运动的原因 '''
    if rect_direction == 'UP':
        rect_y -= rect_speed
    elif rect_direction == 'DOWN':
        rect_y += rect_speed
    elif rect_direction == 'LEFT':
        rect_x -= rect_speed
    elif rect_direction == 'RIGHT':
        rect_x += rect_speed

4、如果正方形撞到窗口外怎么办？以下是我给出的方案，即让正方形返回运动：

    if rect_x < 0:
        rect_direction = 'RIGHT'
    elif rect_x > width:
        rect_direction = 'LEFT'
    elif rect_y < 0:
        rect_direction = 'DOWN'
    elif rect_y > height:
        rect_direction = 'UP'

5、为了让正方形运动时不显示出运动的轨迹和运动的速度不太快，一下的代码就是重中之重：

    #更新画面
    screen.fill((0,0,0))

    #画出正方形
    pygame.draw.rect(screen,rect_color,(rect_x,rect_y,rect_width,rect_height),rect_size)

    # 更新显示 
    pygame.display.flip()  

    # 控制帧率 
    pygame.time.Clock().tick(10) 

    #刷新游戏窗口
    pygame.display.update()

6、关闭窗口（常规操作）

总而言之，整体难度还是比较大的，主要难点是运动的逻辑，这个需要自己在坐标轴上去推理。真的希望我能坚持下去，能够把既定的目标完成，真的。

与君共勉，下期再见